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Pertanyaan

sebanyak 1,492 gram Hg2SO4 larut dalam 1.000cm3 air murni.Ksp HgSO4 sebesar....mol/L (Ar : Hg = 200,6, S = 32, O = 16)

1 Jawaban

  • Mr Hg2SO4 = (2×200)+32+(4×16) = 496
    1000 cm3 = 1 dm3 = 1 liter

    n Hg2SO4 = massa/Mr = 1,492/496 = 0,003

    Ksp = n Hg2SO4/volume
    = 0,003/1 liter
    = 0,003 mol/L

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