Jika f(x)=(x-2)kuadrat-2(x-1)simetri dari f(x))

FUNGSI KUADRAT

f(x) = (x-2)^2 - 2(x - 1)
f(x) = (x^2 - 4x + 2) - 2x + 2
f(x) = x^2 - 4x + 2 - 2x + 2
f(x) = x^2 - 6x + 4

a = 1 ; b = -6 ; c = 4

sumbu simetrinya :
x = -b/2a
x = -(-6)/2×1
x = 6/2
x = 3

jd sumbu simetrinya x = 3

smga mmbantu