Jika titik a(6,4,-2), b(4,3,x), dan c(0,1,10) segaris, nilai x = ... ?

ab = kbc
b - a = kc - kb
(4,3,x) - (6,4,-2) = k(0,1,10) - k(4,3,x)
(-2, -1, x+2) = (0, k, 10k) - (4k, 3k, kx)
(-2, -1, x+2) = (-4k, -2k, (10-x)k)

-2 = -4k => k = 1/2

-1 = -2k => k = 1/2

x+2 = (10-x)k
x+2 = 10k - xk
x + 2 = 10×1/2 - x ×1/2
x+2 = 5 - x/2
x+ x/2 = 5-2
3x/2 = 3
x = 3 × 2/3
x = 6/3
x = 2

moga mmbantu