jika massa atom relatif S=32,Al=27,O=16,H=1,hitunglah massa molekul relatif Al2(SO4)3.18H2O
Kimia
helly4
Pertanyaan
jika massa atom relatif S=32,Al=27,O=16,H=1,hitunglah massa molekul relatif Al2(SO4)3.18H2O
2 Jawaban
-
1. Jawaban ionkovalen
Al2(SO4)3.18H2O
Al = 54
S = 96
O = 192
H2O = 324
total Mr Al2(SO4)3.18H2O = 666 -
2. Jawaban RahmatDarmaraga
Mr Al2(SO4)3.18H2O
= 2xAr Al + 3xAr S + 12 x Ar O + 36 x Ar H + 18 x Ar O
= 54 + 96 + 192 + 36 + 288
= 666