Matematika

Pertanyaan

Persamaan garis melalui titik (-2, 5) dan tegak lurus garis 2x-3y = -12 adalah..

2 Jawaban

  • 2x - 3y = -12
    m1 = -a/b = -2/-3 = 2/3

    m1 . m2 = -1
    2/3 . m2 = -1
    m2 = -1 x 3/2
    m2 = -3/2

    y-y1 = m(x-x1)
    y-5 = -3/2(x-(-2)
    y-5 = -3/2(x+2)
    2(y-5) = -3(x+2)
    2y-10 = -3x-6
    3x + 2y - 10 + 6 = 0
    3x + 2y - 4 = 0
  • mencari gradien
    2x - 3y = -12
    3y = 2x + 12
    y = 2/3 x + 4
    m1 = 2/3
    m2 = -3/2

    persamaan garis
    y - y1 = m(x - x1)
    y - 5 = -3/2(x + 2)
    y = -3/2 x - 3 + 5
    y = -3/2 x + 2
    2y = -3x + 4

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