Persamaan garis melalui titik (-2, 5) dan tegak lurus garis 2x-3y = -12 adalah..
Matematika
aldiskypeer
Pertanyaan
Persamaan garis melalui titik (-2, 5) dan tegak lurus garis 2x-3y = -12 adalah..
2 Jawaban
-
1. Jawaban zahraaryoko
2x - 3y = -12
m1 = -a/b = -2/-3 = 2/3
m1 . m2 = -1
2/3 . m2 = -1
m2 = -1 x 3/2
m2 = -3/2
y-y1 = m(x-x1)
y-5 = -3/2(x-(-2)
y-5 = -3/2(x+2)
2(y-5) = -3(x+2)
2y-10 = -3x-6
3x + 2y - 10 + 6 = 0
3x + 2y - 4 = 0 -
2. Jawaban andhikahanif
mencari gradien
2x - 3y = -12
3y = 2x + 12
y = 2/3 x + 4
m1 = 2/3
m2 = -3/2
persamaan garis
y - y1 = m(x - x1)
y - 5 = -3/2(x + 2)
y = -3/2 x - 3 + 5
y = -3/2 x + 2
2y = -3x + 4