persamaan garis yang melalui titik A(-2,-5) dan B(3,-7) adalah

( -2 , -5) dan (3 , -7)
Pakai rumus :
(y - y1 )/( y2 - y1) = (x - x1) / (x2 - x1)
(y - (-5)) / (-7 -(-5)) = (x - (-2)) / ( 3 -(-2))

(y + 5) / (-2) = (x + 2) / 5
-2(x + 2) = 5(y+ 5)
-2x - 4 = 5y + 25
0 = 5y + 25 + 2x + 29
2x + 5y + 29 = 0

m=y2-y1/x2-x1 = -7+5 / 3+2= -2/5
y-y1=m(x-x1)
y+5=-2/5(x+2)
y+5=2/5x+4/5
y×5/2x= 4/5-5
___________×10
10y.25x=8-50
25x.10y= -42
25x.10y+42=0
sorry kalo salah