1.) maaf ya kebalik pertanyaan di gambar. 2.) Diketahui volume suatu tabung 175phi*3 . bila diameter tabung 10 cm . luas tabung adalah... 3.) Tinggi kerucut den

1).
a = 8 m
b = 6 m
t = 12 m

c = √(a² + b²)
c = √(8² + 6²)
c = √(64 + 36)
c = √100
c = 10 m

Luas prisma = 2(6 × 8)/2 + (6 × 12) + (8 × 12) + (10 × 12)
= 2(48)/2 + 72 + 96 + 120
= 48 + 72 + 96 + 120
= 336 m²

Biaya yang diperlukan = Rp40.000,00 × 336
= Rp13.440.000,00

2). r = 1/2 × d = 1/2 × 10 = 5 cm
Volume = π × r² × t
175π = π × 5² × t
175π = 25π × t
t = 175/25
t = 7π cm

Luas = 2πr.t + 2πr²
= (2 × π × 5 × 7) + (2 × π × 5²)
= 70π + 50π
= 120π cm²

3). r = 1/2 × d = 1/2 × 14 = 7 cm
Luas selimut = π × r × s
550 = 22/7 × 7 × s
550 = 22 × s
s = 550/22
s = 25 cm

t = √(s² - r²)
t = √(25² - 7²)
t = √(625 - 49)
t = √576
t = 24 cm

Jadi, tingginya adalah 24 cm

4). r = 1/2 × d = 1/2 × 30 = 15 cm

Volume = 1/3 × π × r² × t
4.710 = 1/3 × 3,14 × 15² × t
4.710 = 1/3 × 3,14 × 225 × t
4.710 = 1/3 × 706,5 × t
4.710 = 235,5 × t
t = 4.710/235,5
t = 20 cm

t² = s² - r²
20² = s² - 15²
400 = s² - 225
400 + 225 = s²
625 = s²
s = √625
s = 25 cm

Luas sisi = πr (s + r)
= 3,14 × 15 (25 + 15)
= 47,1 × 40
= 1.884 cm²

5). r = 1/2 × d = 1/2 × 28 = 14 cm
Luas permukaan belahan bola
= 1/2 × 4 × π × r²
= 2 × 22/7 × 14²
= 2 × 22/7 × 196
= 2 × 616
= 1.232 cm²