Matematika

Pertanyaan

1 + sin x / Cos x + Cos x / 1 + sin x = 2 sec x
1 + sin x / Cos x + Cos x / 1 + sin x = 2 sec x

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  • 1 + sinx / cosx + cosx / 1 + sinx = 2secx

    (1 + sinx)(1 + sinx) + cos²x / cosx (1 + sinx) = 2secx

    1 + 2sinx + sin²x + cos²x / cosx (1 + sinx) = 2secx

    1 + 2sinx + 1 / cosx (1 + sinx) = 2secx

    2 + 2sinx / cosx (1 + sinx) = 2secx

    2 (1 + sinx) / cosx (1 + sinx) = 2secx

    2 / cosx = 2 secx

    2 (1 / cosx) = 2secx

    2secx = 2secx

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