Luas daerah yg di arsir

L1 (trapesium)
= ½(a+b)t
= ½(10+(12+8))(6+8)
= ½(10+20)(14)
= 7(30)
= 210 cm²

L2 (segitiga siku")
= ½ at
= ½ (12) (8+6+4)
= 6(18)
= 108 cm²

L3 (tdk diarsir)
= ½ at
= ½ (12)(8)
= 6(8)
= 48 cm²

L diarsir
= L1 + L2 - (2.L3)
= 210 + 108 - (2.48)
= 318 - 96
= 222 cm²