Persamaan garis yang melalui titik (-3,-4) dan bergradien 2/3 adalah... A.2x-3y-6=0 B.2x-3y+6=0 C.3x-2y+1=0 D.3x+2y-1=0

Pakai rumus
y - y1 = m(x - x1)
y - (-4) = 2/3 ( x - (-3))
y + 4 = 2/3 (x + 3)
---------------------------- ×3
3y + 12 = 2(x + 3)
3y + 12 = 2x + 6
0 = 2x + 6 - 3y - 12
2x - 3y - 6 = 0 (A.)

y - y1 = m (x - x1)
y - (-4) = 2/3 (x - (-3))
y + 4 = 2/3 (x + 3)
y + 4 = 2/3x + 2
-2/3x + y + 4 -2 = 0
-2/3x + y + 2 = 0
semua ruas dikali -3
2x - 3y - 6 = 0 (a.)