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Pertanyaan

Lim x→0 [ ( x^2 - 4 ) . ( tan2x )^2 ] : [ x^4 + 3x^3 + 2x^2 ]

Ctt:
^angka = pangkat bilangan

1 Jawaban

  • Lim (x² - 4) (tan2x)²
    x→0 .. / x^4 + 3x^3 + 2x²

    Lim (x² - 4) (tan2x)²
    x→0 .. / x² (x² + 3x + 2)

    Lim (x - 2)(x + 2) (tan2x)²
    x→0 .. / x² (x + 2)(x + 1)

    Lim (x - 2)(tan2x)²
    x→0 .. / x² (x + 1)

    Lim (tan2x/x)² ((x - 2) / (x + 1))
    x→0

    Lim (2)² (x - 2) / (x + 1)
    x→0

    = 4 (-2) / 1

    = -8 / 1

    = -8

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