Lim x→0 [ ( x^2 - 4 ) . ( tan2x )^2 ] : [ x^4 + 3x^3 + 2x^2 ] Ctt: ^angka = pangkat bilangan
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Pertanyaan
Lim x→0 [ ( x^2 - 4 ) . ( tan2x )^2 ] : [ x^4 + 3x^3 + 2x^2 ]
Ctt:
^angka = pangkat bilangan
Ctt:
^angka = pangkat bilangan
1 Jawaban
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1. Jawaban Robinn
Lim (x² - 4) (tan2x)²
x→0 .. / x^4 + 3x^3 + 2x²
Lim (x² - 4) (tan2x)²
x→0 .. / x² (x² + 3x + 2)
Lim (x - 2)(x + 2) (tan2x)²
x→0 .. / x² (x + 2)(x + 1)
Lim (x - 2)(tan2x)²
x→0 .. / x² (x + 1)
Lim (tan2x/x)² ((x - 2) / (x + 1))
x→0
Lim (2)² (x - 2) / (x + 1)
x→0
= 4 (-2) / 1
= -8 / 1
= -8