Tentukan Ph larutannya dari amonium sulfat ( NH4) 2SO4 0,1 M: Kb NH3=1,8*10-5

(NH4)2SO4

[H+] = √Kw / Kb . n [kation]
[H+] = √(10^-14 / 1,8 x 10^-5) . 2 . 1 x 10^-1
[H+] = √(10^-14 / 18 x 10^-6) . 2 . 10^-1
[H+] = √(10^-8 / 18) x 2 x 10^-1
[H+] = √10^-9 x 1/9
[H+] = 1/3 x √10^-8 x 10^-1
[H+] = 1/3 x 10^-4√0,1
[H+] = 1/3√0,1 x 10^-4

pH = - log [H+]
pH = - log 1/3√0,1 x 10^-4
pH = 4 - log 1/3√0,1
pH = 4 - 0,1
pH = 3,9