berapa gram kristal NH4 (4 dibawah)CI diperlukan untuk membuat 500ml larutan dengan ph=5 (Ar H=1 n=14 CI 35,5 kb=10 pangkat -5)?

NH4Cl

pH = 5
pH = -log[H+]
[H+] = 10^-5

[H+] = √Kw/Kb . M
10^-5 = √10^-14 / 10^-5 . M
10^-5 = √10^-9 . M
10^-10 = 10^-9 . M
M = 10^-10 / 10^-9
M = 10^-1
M = 0,1 M

Mr = 14 + 4 + 35,5
Mr = 53,5

n = M . v
n = 0,1 M . 0,5 L
n = 0,05 mol

gr/mr = n
gr = Mr . n
gr = 53,5 . 0,05
gr = 2,675 gram