f(x)=1/√x +^3√2x berapa nilai f'(x)?

[tex]f(x) = \frac{1}{\sqrt{x} } + \sqrt[3]{2x}\\\\ f(x) = x^{-1} + (2x)^{\frac{1}{3}} \\\\ f'(x) = -x^{-2} + \frac{1}{3}(2x)^{-\frac{2}{3}} \\\\ f'(x) = - \frac{1}{x^{2}} + \frac{1}{3} \frac{1}{\sqrt[3]{(2x)^{2}}}[/tex]