50 mL larutan NH3 0,1 M dengan 50 mL larutan NH4CL 0,3 M?
Kimia
RullBee
Pertanyaan
50 mL larutan NH3 0,1 M dengan 50 mL larutan NH4CL 0,3 M?
1 Jawaban
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1. Jawaban Robinn
→ mol NH3
= 50ml x 0,1
= 5mmol
→ mol NH4Cl
= 50ml x 0,3
= 15mmol
pOH = pKb - log b/g
pOH = -log10^-5 - log 5/15
pOH = 5 - log1/3
pOH = 5 - (- 0,4)
pOH = 5 + 0,4
pOH = 5,4