tentukan pH larutan garam (CH3COO)2Ca 0,004 M. jika Ka CH3COOh=2×10-5...

(CH3COO)2Ca → 2CH3COO- + Ca2+

[OH-] = √Kw/Ka . n [anion]
[OH-] = √10^-14 / 2 x 10^-5 . 2 . 4 x 10^-3
[OH-] = √10^-9 . 4 . 10^-3
[OH-] = √4 x 10^-12
[OH-] = 2 x 10^-6

pOH = -log [OH-]
pOH = -log 2 x 10^-6
pOH = 6 - log2

pH = 14 - pOH
pH = 14 - (6 - log2)
pH = 14 - 6 + log2
pH = 8 + log2