Terdapat 4 L larutan NH4Cl 0,01 M. Jika konstanta hodrolisis (Kh)=10-5 maka pH larutan garam tersebut adalah...

Kh = Kw / Kb
10^-5 = 10^-14 / Kb
Kb . 10^-5 = 10^-14
Kb = 10^-14 / 10^-5
Kb = 10^-9

pH = 1/2 (14 - pKb - log[G])
pH = 1/2 (14 - (-log10^-9) - log10^-2)
pH = 1/2 (14 - 9 + 2)
pH = 1/2 (7)
pH = 3,5