diketahui koordinat titik A(4 -3,8) B(-1,2,5). jika vektor AB:AC = 3:2, koordinat titik C adalah…

misal
C = (a,b,c)
AB=B-A = (-1-4, 2-(-3), 5-8) = (-5,5,-3)
AC=C-A=(a-4, b+3, c-8)
krn AB:AC = 3:2 maka AC=2/3 AB
shgga
2/3 (-5,5-3) = (a-4, b+3, c-8)

2/3 *(-5) =a-4
-10 =3(a-4)
-10=3a-12
-10+12=3a
a=2/3

2/3 * 5 = b+3
10 = 3(b+3)
10=3b+9
10-9=3b
1=3b
b=1/3

2/3 *(-3)=c-8
-6=3(c-8)
-6=3c-24
-6+24=3c
18=3c
c=6


koordinat C adlh (2/3,1/3,6)