Massa = 0,3 gram NH4NO3 V = 250 ml, kb = 2×10^-5, Mr = 80, (Berapa PH) ?
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Massa = 0,3 gram NH4NO3 V = 250 ml, kb = 2×10^-5, Mr = 80, (Berapa PH) ?
1 Jawaban
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1. Jawaban sandysuhendra
n = 0,3/80 = 3,75×10^-3 mol
M = n/V = 3,75×10^-3/0,25 = 0,015 M
[H+] =√(Kw/Kb × M) = √(10^-14/2×10^-5 × 0,015) = √(7,5×10^-12) = 2,74×10^-6 M
pH = - log (2,74×10^-6) = 6 - log 2,74 = 5,56