hidrolisis garam ka CH3COOH = 0,9M 100 ml (Tentukan PH) ?

itu garamnya garam ASAM jadi rumus =
(OH^-) = √kw÷ka × M(garam asam)
          = √10^-14 ÷ 10^-5 × 9×10^-1
          = √9×10^-10
          = 3×10^-5
pOH   = -Log(OH)
           = -log 3×10^-5
pOH    = 5- log3
pH    = 14-(5- log3)
pH     = 9+log3