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Pertanyaan

Hitung lah [H+] dan [OH-] yg terdapat falam larutan NH4OH 0,4 M. (Kb=1×10-5)

1 Jawaban

  • [OH-] = √kb . [NH4OH]
    [OH-] = √10^-5 . 4 x 10^-1
    [OH-] = √4 x 10^-6
    [OH-] = 2 x 10^-3

    [OH-] [H+] = Kw
    2 x 10^-3 [H+] = 10^-14
    [H+] = 10^-14 / 2 x 10^-3
    [H+] = 10^-11 / 2
    [H+] = 0,5 x 10^-11

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